The function of the trolley line system and its spare parts

Driving trolley line important device

Collector is an important installation for picking up electric energy on the collector side of the trolley wire. It passes through the sliding contact of the collector brush and the guide rail, and indirectly conducts the electric energy to the electric appliance, thereby completing the fragmented mobile power supply. The current collector is composed of two parts, a mechanically-configured tensioner and a collector brush that is in sliding contact with the guide rail indirectly.

Tension installation of the mechanical structure determines the sliding contact pressure of the collector brush and the guide rail and the stability of the mechanism. The collector brush is a conductor of the guide rail sliding contact and picks up the electric energy. Its function and conductive quality and the merits of the data construction component will be indirect. Affect the quality of the safe operation of all fragmented equipment.

The trolley wire is used to power the moving equipment. It consists of two parts, slide rail (fixed part, connected to the power supply, often the guide rail is made of single length 4m/root or 6m/root), collector ( Sliding part, can slide on or within the slide rail and contact with the copper bar to take electricity, the collector is used to connect with the moving motor).

Calculation of the number of parts of the trolley wire system

1. The most basic components of the trolley line system. The most basic trolley line system should include the following component guides (including insulation jacket).

Connector (with joint jacket)

Conductor pendant (and pendant bracket)

Mounting clip end parts Power input parts Expansion parts Collector mounting brackets for current collectors 2. Slippery wire system Other possible parts Insulating parts Pick-up guides 3. Steps for the calculation of the number of parts on the trolley wire Consider whether expansion is required Selection of component guides specification Considering the position and number of feed points Calculate the number of guides Calculate the number of joints and jackets Calculate the number of fixing clamps Calculate the number of lifting attachments Calculate the number of current collectors and brackets 4. Calculate the number of expansion components Consider Do you need expansion parts SL2- When the system length is less than 150 meters, no expansion parts are required.

The SL3-system is less than 200 meters in length without the need for expansion components.

Determining the Number of Expansion Parts When the system needs an expansion part, the number of expansion parts is determined according to the following formula.

n=(Tamax-Tamin)×(L-L0)×1000×ce/exp

The number of n-expansion parts Tamax - the maximum allowable temperature of the trolley wire (PVC sheath is 80°C, PPO sheath is 120°C)

Tamin - The lowest possible temperature in the field L - The actual length of operation of the system in meters

L0 - Maximum system length (unit: meters) without expansion components

Ce-expansion coefficient (galvanized steel-0.0000126/copper-0.0000162/aluminum-0.0000235)

Exp - working range of the expansion part (unit: mm)

SL2-50 mm SL3-200 mm Example: A 180-meter-long system with a minimum ambient temperature of -10°C using a standard aluminum conductor.

If using SL3 conductors do not need to configure expansion components.

If the SL2 conductor is used, an expansion member n=(80-(-10))×(180-150)×1000×0.0000235÷50≈1.3 is needed

If the value of n is a decimal, then no matter how big the decimal is, it needs to carry. In the above example, each phase (and each root) needs to expand two components. It should be noted that the same conditions use conductors of different materials and the number of expansion components is different.

For example: a 180-meter-long system with a minimum ambient temperature of -10°C using standard SL2 copper conductors. n = (80 - (-10)) x (180 - 150) x 1000 x 0.0000162 ÷ 50 ≈ 0.9 The same conditions for copper conductors and galvanized steel conductors require fewer expansion members than aluminum conductors.

5. Selection of guide bar specifications For systems with 380 V power supply, the running current of the vehicle is approximately twice the total power.

For a system that contains more than one vehicle, the total operating current of the system needs to consider the following conditions.

- One lane: The largest two motors in all the lanes - Two lanes: The largest three motors in all motors - Three lanes: The largest three motors in all motors - Four lanes: The largest of all motors After determining the operating current of the system, Taiwan Motor determines the coefficient (K) based on the following ambient temperature (Ta) and the Duty (Duty) coefficient. The actual allowable current of the guide rod is I = nominal current × K. It is necessary to select a guide rod whose I is greater than the actual operating current of the system.

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